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1832 presidential election map and results

Andrew Jackson won reelection with 219 electoral votes. Henry Clay won 49, William Wirt seven, and John Floyd eleven. A majority was 144 of 286 electoral votes.

Map of the 1832 presidential election results by state
Jackson (Democratic)Clay (National Republican)Wirt (Anti-Masonic)Floyd (Nullifier)Did not vote / not yet a state

Explore the 1832 map interactively →

Candidates

CandidatePartyElectoral votesPopular vote%
Andrew Jackson ✓Democratic219701,78054.2%
Henry ClayNational Republican49484,20537.4%
William WirtAnti-Masonic7100,7157.8%
John FloydNullifier1100.0%

Popular-vote totals add up the states with recorded votes; some states chose electors through their legislatures in this era.

Results by state

StateWon byElectoral votesWinner %Margin (pts)
AlabamaAndrew Jackson7100.0%99.9
ConnecticutHenry Clay855.3%21.0
DelawareHenry Clay351.0%2.0
GeorgiaAndrew Jackson11100.0%100.0
IllinoisAndrew Jackson568.0%36.6
IndianaAndrew Jackson955.4%10.8
KentuckyHenry Clay1554.5%9.0
LouisianaAndrew Jackson561.7%23.3
MaineAndrew Jackson1054.7%10.7
Maryland *Henry ClayClay 5, Jackson 350.0%0.0
MassachusettsHenry Clay1447.3%25.5
MississippiAndrew Jackson4100.0%100.0
MissouriAndrew Jackson4100.0%100.0
New HampshireAndrew Jackson756.8%13.5
New JerseyAndrew Jackson849.9%0.8
New YorkAndrew Jackson4252.1%4.2
North CarolinaAndrew Jackson1584.8%69.5
OhioAndrew Jackson2151.3%3.0
PennsylvaniaAndrew Jackson3057.7%15.4
Rhode IslandHenry Clay450.0%14.3
South Carolina *John Floyd11——
TennesseeAndrew Jackson1595.4%90.8
VermontWilliam Wirt740.5%6.0
VirginiaAndrew Jackson2375.0%49.9

Notes

← 1828 electionAll elections1836 election →

Sources